Re: [ns] TCP sequence number

[Brian Lee Bowers <bowersb@lanl.gov>]

On Thursday 02 August 2001 12:36, Qingjuan Gu wrote:
> Dear all,
>
> I want to calculate the duplicated packets in tcp through
> sequence number. but I am wondering if the sequence number is
> wrapped round. Does anybody can explain this question

The basic TCP implementations (Agent/TCP, Agent/TCP/Reno, 
Agent/Newreno, and Agent/Vegas) simplify sequence numbers in the 
following two ways:
	all connections start their sequence numbers at 0
	sequence numbers count packets, not bytes

(I don't work with Full TCP, so I'm not qualified to say 
anything about how it implements sequence numbers).

Sequence numbers are signed 32 bit ints, so you've got 2G worth of 
packets before you start getting into strange numbers for sequence 
numbers.  Are you going to have a single flow send more than 2 
billion packets in your simulations?

-- 
Brian Lee Bowers	|	RADIANT Team (Summer Intern)
bowersb@lanl.gov	|	Los Alamos National Laboratory